How do you calculate the RMS value for a square wave with peak-to-peak voltage of 4V and a 2V DC offset? - rms voltage of a square wave with dc offset
AC RMS does not mean DC
Square wave 50% duty cycle means that half of the peak to peak
C
Thursday, January 28, 2010
Rms Voltage Of A Square Wave With Dc Offset How Do You Calculate The RMS Value For A Square Wave With Peak-to-peak Voltage Of 4V And A 2V DC Offset?
2 comments:
RMS means root instead of the mean (average). 4 Move the Vpp square wave voltage (2 half the time, and -2 means half) with a V 2 4 volts, half the time, and zero volts, half the time. 4 squared is 16, and 0 square is equal to zero, so that the same time (on average, a cycle or a whole number of cycles) which is two (16 +0) / 2 = 8. Take the square root of 8 for the RMS value.
So, this heat wave, when a resistance of 2828 volts DC, which shows how the value of the wave.
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Regards,
John Popelish
The RMS value of 2 volts DC volt signal 2
The RMS of a square wave voltage with a tip to the voltage of 4 V peak is 2 volts
The RMS voltage of the sum signal is equal to the square root of the sum of the RMS voltage squared sqrt (2 ^ 2 + 2 ^ 2) = 2828 volts. The answer is 2828 volts RMS
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